x^2+x-5700=0

Solution for x^2+x-5700=0 equation:

x^2+x-5700=0

a = 1; b = 1; c = -5700;
Δ = b2-4ac
Δ = 12-4·1·(-5700)
Δ = 22801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22801}=151$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-151}{2*1}=\frac{-152}{2}
=-76
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+151}{2*1}=\frac{150}{2}
=75
$